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FIR IP filter output waveform shake up and down ,

Input signal contains the useful signal and the noise signals , so the frequency of the noise signal may be greater than half of the sampling frequency of the filter , what I want from the output of the FIR IP filter is just the useful signal , so should the the sampling frequency of the filter must ust be much greater than twice the frequency of all input signal include the noise signal ??? and why FIR IP filter output waveform shake up and down ??? Looking for your helping reply , thank you very much !!!Link Copied

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So you have two single tones coming from ADC; one at 1Hz, and one at 1KHz and you want to filter off the 1Khz and pass the 1 Hz

You haven't said anything about Fs of signal itself. You have chosen Fs of 1KHz first then FS of 5KHz. You can't just pick a value. Your Fs must be that of input signal and should be same as ADC Fs unless you have done downsampling which I doubt.- Mark as New
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You better try IIR filter such as the leaky integrator where:

y(n) = alpha*y(n-1) + (1-alpha)*x(n); alpha from 0 ~ <1 to control cutoff point.Topic Options

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