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On another note, are there separate floating-point execution units supporting the various SSE or MMX instructions ? Or are the same execution units with those used for the regular FP instructions ? As far as I can tell, Nehalem cores have 5 exec. unit 2 of which can carry out double-precistion FP calculation + a 3rd unit doing FPshuffles, correct ?
What is the "thoretical" Maximuym FLOPS performance of a Nehalem CORE running at 2.8GHz (no turbo) ?
Thanks for any info on these......
Michael
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Each core has its own execution units as you can find out from that article. Also, you may want to read more in Software
Intel 64 and IA-32 Architectures Optimization Reference Manual at http://www.intel.com/products/processor/manuals/
Regarding flops.2.8GHZ with 4 corescan support 90GFLOPS
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I was wondering what would be the rate of floating-point ops / sec for a Nehalem core. From their h/w docs it appears that each core has 6 execution units from which only 2 can carry out FP arithmetic ops (the 3rd one can do FP shuffle and the other 3 are for mem access). For the FLOPS (FP ops / sec) I cannot see how this can be > 3 / cycle.
If you take a look at :
http://www.intel.com/products/processor/manuals/ the "Intel 64 and IA-32 Architectures Optimization Reference Manual " (pp.2.21 2.2 INTEL MICROARCHITECTURE (NEHALEM)) or presentations at IDF Aug. 2008 you can see that all micro-ops are routed via 6 ports to the execution units 2 (or 3 with abuse of logic) can deliver FP results and quoting pp 2.23
" The scheduler (or reservation station) can dispatch up to six micro-ops in one cycle
through six issue ports (five issue ports are shown in Figure 2-5; store operation
involves separate ports for store address and store data but is depicted as one in the
diagram).
The out-of-order engine has many execution units that are arranged in three execu-
tion clusters shown in Figure 2-5. It can retire four micro-ops in one cycle, same as
its predecessor."
See then p 2.26 where the FP unis can indeed retire 1 op / cycle ("latency =1") but with 3 FP unis the best you can do is to retire 3 FPops/cycle or 3 X ClockHz. In the 2.8GHz case I can see
3x2.8GHz = 8.4Gflops/sec
ONLY if there are MORE units than those shown which can carry out FP arithmetic I can justify a number > 8.4Gflops/sec / core.
That is why I posed the question if the varios SIMD or XMM instructions utilize different FP units from those in the main core pipelines.
thanks for replying to my comment.....
Michael
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You are absolutely right Core i7 can retire 4 instructutions/cycle. Regarding your calculations:
3x2.8GHz = 8.4Gflops/sec
you need to multiply this number with SIMD Width ie. 4 FP (32bit) per cycles. Secondly, you are also missing number of cores in the system as COREi-7 is not a single core machine as far as i know.
Assuming theoreticaly you are doing three 32 bit floating point instructions on three different execution engines then GFLOPS are:
3x2.8ghz x 4 (SIMD WIDTH) x 4 (number of cores) = 134GFLOPS
My above caluclations (previous reply) were based on 2 execution engines.
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I am trying to udnerstand about the "you need to multiply this number with SIMD Width ie. 4 FP (32bit) per cycles."
Can you explain this a little more to me or point to documentation that explains it?
This is how I see the 4 SP ops / FP UNIT (ai, bi. ci 32-bit SP numbers)
c1= a1 FPa b1
c2= a2 FPa b2
c3= a3 FPa b3
c4= a4 FPa b4
where FPa is an operation which is applied in SIMD fashion to 4 different pairs of operands but
this implies 4 separate FP ALU units capable of delivering 4 (pipelined) results every clock.
For this to work this means that the 2 FP units (via Port 0 and Port1) are really 8 separete SP ALUs ? Can I also asssume that these eight units can writeback 8 operands / clock cycle ?
So the 2 FP ops retiring / cycle <=> 8 date results produced / cycle?
If this is indeed the case it is nowever stated clearly that there are really 4 FP ALUS per FP unit. Or I just missed it ....
thanks for the reply ...
Michael
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H Tim, so we can say then that there are indeed 4 32-b FP ALUs per FP capable port (or their equivalent). One could execute the same OP on quadtruple operands in a vector/pipelined fashion which means 1 result (vs 4) produced / clock.
When the manual says that Nehalem can retire 4 micro-ops / cycle, this includes two 4-way SP or two 2-way DP SIMD ones, right?
Can we use any of the tools (eg, VT) to assess how successfully a compiler packs operands to use the SIMD arithmetic ops in code?
thanks ... Michael
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thanks,
-Max
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thanks,
-Max
Hi Max,
thanks for the pointer. I like the definite answers. You can understand that due to my ignorance in how the SIMD FPs are implemented within the Nehalem core I could only see the vectorized or the true SIMD approach and docs are not definite in this respect.
I am "new" to Intel64 ISA and its microarchitectures (I did ASM back in late 80s ... :)
BTW, is there any document which discusses the implementation of microarch in detail outside the standard Intel Docs?
cheers ....
Michael
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Hi Tim,
thanks for the definite answer for this.
Everything started when the question was posed to me "what is the theoretical MAX FP performance of Nehalem cores?" I thought is should asymptotically be bounded by sustained rate of FP operation retirement in the core but then it wasn't clear to me if up to 4 SP FPs / cycle / issue port (SIMD) or 1 SP FPs / cycle / issue port (vector with pipelined ALUs) .
Thanks again. I will come back to maybe torture other answers out of the forum (maybe some uncore implementation stuff, L3 to core to QPI connection capbilities, etc. ;;)
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here is one old albeit good reference : Inside Nehalem: Intel's Future Processor and System
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>maybe some uncore implementation stuff
here is another old albeit good reference about QPI : The Common System Interface: Intel's Future Interconnect
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